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Managerial Accounting covers cost behavior, cost-volume-profit analysis, job and process costing, budgeting, and variance analysis. Exams are procedural — allocate these overheads, compute these variances, build this budget — and reward tidy, labeled working. Practicing full problems against worked solutions makes the formats automatic before the clock is running.

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Topics typically tested

  • Cost behavior & classification
  • Cost-volume-profit analysis
  • Job-order & process costing
  • Activity-based costing
  • Master budgets
  • Standard costs & variance analysis

Sample Managerial Accounting exam questions

Three original questions in the style of a real Managerial Accounting exam, each with a worked solution. Your own practice exam can be built from your course's notes and syllabus.

Question 1Multiple choiceCost-volume-profit analysis

Northfield Gear sells one product for $50 per unit. Variable cost is $30 per unit and fixed costs are $120,000 per year. The company's income tax rate is 25%. How many units must it sell to earn an after-tax profit of $30,000?

  1. A.

    6,000 units

  2. B.

    7,500 units

  3. C.

    7,875 units

  4. D.

    8,000 units

Worked solution
Answer:D

CVP analysis works in pre-tax dollars, so the first step is to convert the after-tax target into the operating income needed before tax:

Pre-tax income=After-tax income1−t=30,0001−0.25=40,000\text{Pre-tax income} = \frac{\text{After-tax income}}{1 - t} = \frac{30{,}000}{1 - 0.25} = 40{,}000

Next find the contribution margin per unit, the amount each sale contributes toward covering fixed costs and then profit: $50 − $30 = $20 per unit.

Units needed to cover fixed costs and earn the pre-tax target:

Q=Fixed costs+Target pre-tax incomeCM per unit=120,000+40,00020=8,000Q = \frac{\text{Fixed costs} + \text{Target pre-tax income}}{\text{CM per unit}} = \frac{120{,}000 + 40{,}000}{20} = 8{,}000

Check: 8,000 units give a contribution margin of $160,000; less fixed costs of $120,000 leaves operating income of $40,000; tax at 25% is $10,000, leaving $30,000 after tax, which matches the target.

Option B (7,500) is the most tempting error: it plugs the $30,000 after-tax figure straight into the formula without grossing it up for tax. Option C (7,875) grosses up the wrong way, multiplying by 1.25 instead of dividing by 0.75. Option A (6,000) is the break-even point, which ignores the profit target entirely.

Answer: D — 8,000 units.

Question 2Short answerCost behavior & classification

A machine shop's maintenance cost is a mixed cost. Its records for four months are:

MonthMachine-hoursMaintenance cost
January6,400$48,500
February9,000$61,000
March5,000$41,000
April7,500$54,200

Using the high-low method, (a) estimate the variable cost per machine-hour and the monthly fixed cost, and (b) write the cost formula and use it to predict maintenance cost in a month with 7,200 machine-hours.

Worked solution
Answer:

(a) $5 per machine-hour variable; $16,000 fixed per month. (b) Cost = $16,000 + $5 × machine-hours; at 7,200 hours, $52,000.

The high-low method fits a straight line through the observations at the highest and lowest activity levels (not the highest and lowest costs, although here they coincide). Those are February (9,000 hours, $61,000) and March (5,000 hours, $41,000).

(a) Variable cost per hour is the slope between the two points:

Variable rate=61,000−41,0009,000−5,000=20,0004,000=5\text{Variable rate} = \frac{61{,}000 - 41{,}000}{9{,}000 - 5{,}000} = \frac{20{,}000}{4{,}000} = 5

so $5 per machine-hour.

Fixed cost is whatever remains after removing the variable portion at either point. Using February: $61,000 − ($5 × 9,000) = $61,000 − $45,000 = $16,000. Using March gives the same figure, $41,000 − $25,000 = $16,000, which confirms the arithmetic.

(b) Cost formula and prediction. The maintenance cost line is

Y=16,000+5XY = 16{,}000 + 5X

where XX is machine-hours and YY is total maintenance cost in dollars. For 7,200 hours: $16,000 + $5 × 7,200 = $16,000 + $36,000 = $52,000.

Two cautions a grader expects you to know: the estimate is only valid inside the relevant range (5,000 to 9,000 hours), and because the method uses just two data points it is less reliable than a regression on all four months. The January and April observations fall close to the line (predicted $48,000 and $53,500 against actual $48,500 and $54,200), which suggests the fit is reasonable here.

Answer: (a) $5 per machine-hour, $16,000 fixed per month; (b) Y = $16,000 + $5X, giving $52,000 at 7,200 hours.

Question 3Worked problemStandard costs & variance analysis

Harbour Furniture makes a single model of stool. Standard cost data per stool: direct materials 3 kg of hardwood at $4.00 per kg; direct labour 0.5 hours at $20.00 per hour. In May the company produced 2,000 stools. It purchased and used 6,300 kg of hardwood at a total cost of $23,940, and direct labour was 1,050 hours at a total cost of $22,050.

Compute the following variances and label each as favourable (F) or unfavourable (U): (a) direct materials price variance; (b) direct materials quantity variance; (c) direct labour rate variance; (d) direct labour efficiency variance. Then (e) give one plausible operational explanation that links the materials variances to each other.

Worked solution
Answer:

(a) $1,260 F; (b) $1,200 U; (c) $1,050 U; (d) $1,000 U; (e) for example, cheaper, lower-grade hardwood (favourable price) caused more waste or rework (unfavourable quantity) and may also have slowed the workers.

First convert totals to actual rates. Materials: $23,940 ÷ 6,300 kg = $3.80 per kg. Labour: $22,050 ÷ 1,050 h = $21.00 per hour. Standard quantities allowed for 2,000 stools: materials 2,000×3=6,0002{,}000 \times 3 = 6{,}000 kg; labour 2,000×0.5=1,0002{,}000 \times 0.5 = 1{,}000 hours.

(a) Materials price variance isolates paying a different price for the quantity purchased:

(AP−SP)×AQ=(3.80−4.00)×6,300=−1,260(AP - SP) \times AQ = (3.80 - 4.00) \times 6{,}300 = -1{,}260

Paying $0.20 less per kg than standard saves money, so $1,260 F.

(b) Materials quantity variance isolates using a different amount, priced at standard so the price effect is excluded:

(AQ−SQ)×SP=(6,300−6,000)×4.00=1,200(AQ - SQ) \times SP = (6{,}300 - 6{,}000) \times 4.00 = 1{,}200

Using 300 kg more than allowed costs more, so $1,200 U. (Check: the total materials variance is $23,940 − $24,000 = $60 F, and $1,260 F − $1,200 U = $60 F.)

(c) Labour rate variance:

(AR−SR)×AH=(21.00−20.00)×1,050=1,050(AR - SR) \times AH = (21.00 - 20.00) \times 1{,}050 = 1{,}050

Workers were paid $1 per hour above standard: $1,050 U.

(d) Labour efficiency variance:

(AH−SH)×SR=(1,050−1,000)×20.00=1,000(AH - SH) \times SR = (1{,}050 - 1{,}000) \times 20.00 = 1{,}000

Fifty hours more than allowed were used: $1,000 U.

(e) Linking the variances. A favourable price variance paired with an unfavourable quantity variance is the classic sign that purchasing bought cheaper, lower-grade hardwood. Poorer wood splits or has more defects, so more kilograms are consumed per stool, and the extra cutting and rework also helps explain the unfavourable labour efficiency variance. The purchasing department's saving ($1,260) was more than used up on the shop floor ($1,200 + $1,000), which is why variances should be evaluated together rather than one department at a time.

Answer: (a) $1,260 F; (b) $1,200 U; (c) $1,050 U; (d) $1,000 U; (e) cheaper, lower-quality materials leading to more waste and slower work.

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